# CareerTrain - Welding

Urbain et civil

29 nov. 2013 (il y a 4 années et 10 mois)

195 vue(s)

1

Career
Train

Contextualized Learning Packet

Welding Technology

2

Career
Train

Contextualized Learning Packet

Applied Mathematics

Welding Technology

3

What the WorkKeys Applied Mathematics Test Measures

There

are five levels of difficulty. Level 3 is the least complex, and Level 7 is the most complex. The levels
build on each other, each incorporating the skills assessed at the previous levels.

Level

Characteristics of Items

Skills

3

Translate easily from a word
problem to a math equation

All needed information is
presented in logical order

No extra information

Solve problems that require a single
type of mathematics operation
and division) usi
ng whole numbers

Change numbers from one form to
another using whole numbers,
fractions, decimals, or percentages

Convert simple money and time
units (e.g., hours to minutes)

Level

Characteristics of Items

Skills

4

Information may be presented out
of order

May include extra, unnecessary
information

May include a simple chart,
diagram, or graph

Solve problems that require one or
two operations

Multiply negative numbers

Calculate averages, simple ratios,
simple proportions, or rates using
whole numbers and decimals

decimals, or percentages (e.g., 1/2,
.75, 25%)

Add up to three fractions that share
a common denominator

Multiply a mixed numb
er by a whole
number or decimal

Put the information in the right order
before performing calculations

Level

Characteristics of Items

Skills

5

Problems require several steps of
logic and calculation (e.g., problem
may involve completing an order
form by totaling the order and then
computing tax)

Decide what information,
calculations, or unit conversions to
use to solve the problem

Look up a for
mula and perform
single
-
step conversions within or
between systems of measurement

Calculate using mixed units (e.g.,
3.5 hours and 4 hours 30 minutes)

Divide negative numbers

Find the best deal using one
-

and
two
-
step calculations and then
compare resul
ts

Calculate perimeters and areas of
basic shapes (rectangles and
circles)

Calculate percent discounts or
4

markups

Level

Characteristics of Items

Skills

6

May require considerable
translation from verbal form to
mathematical expression

Generally require considerable
setup and involve multiple
-
step
calculations

Use fractions, negative numbers,
ratios, percentages, or mixed
numbers

Rearrange a formula before solving
a problem

Use two formulas to change from
one unit to another within the same
system of measurement

Use two formulas to change from
one unit in one system of
measurement to a unit in another
system of measurement

Find mistakes in questions that
belong at Levels 3,

4, and 5

Find the best deal and use the
result for another calculation

Find areas of basic shapes when it
may be necessary to rearrange the
formula, convert units of
measurement in the calculations, or
use the result in further calculations

Find the vo
lume of rectangular
solids

Calculate multiple rates

Level

Characteristics of Items

Skills

7

Content or format may be
unusual

Information may be
incomplete or implicit

Problems often involve
multiple steps of logic and
calculation

Solve problems that include nonlinear
functions and/or that involve more than one
unknown

Find mistakes in Level 6 questions

Convert between systems of measurement
that involve fractions, mixed numbers,
decimals, and/or percentages

Calculate multiple ar
eas and volumes of
spheres, cylinders, or cones

Set up and manipulate complex ratios or
proportions

Find the best deal when there are several
choices

Apply basic statistical concepts

5

1.

Bob added up the hours on his timecard. He got a total of 37 6/8

hrs.

Reduce his hours to lowest terms.

2.

You need to drill a hole in a piece of metal for an
11
/
16

inch bolt to pass thru

Will a
¾
inch hole be a little too big or little too small?

3.

Arrange these four drill bits in order from smallest (left) to largest (
right)

3
/
8

11
/
32

7
/
16

13
/
32

4.

Which steel bar is longer?

Bar 1 25
1
/
8

inches

or
Bar 2 25
3
/
32

inches

5.

Eleven 2 and1/2 inch pieces are cut from a bar of round stock.

How much material is used?
(Ignore any loss due to cutting
.
)

6.

A rectangular plate which is 36
" w
ide and 49
"
long is to be cut into strips that are 36
"
long and
7
/
8

in. wide
.

Ho
w
many strips can be cut from the p
l
ate?

7.

4
7
/
8

in long pieces are to be cut from a 120" long bar.

How many
complete
pieces can be cut from the bar?

8.

Seven weldments
,
each 1 ¾ in, long
,

What is the total length of weldments?

6

9.

A support bracket as shown below has equally spaced uprights welded to it. If the
distance between the centers of the first and fourth
uprights is 16

½
"

F
ind the distance between the centers of the first and second uprights. 16 1
1
2"

10.

If one piece of angle iron weighs 24
½
lbs., how much will three pieces weigh?

11.

If three tanks of propane gas lasted 22
3
/
8

days, how long did each tank last?

12.

A 7
¼
in piece and a 9
3
/
8

in are cut from a 49" length of round stock
.
If
1
/
8

in. of waste is
allowed for each cut how much of the round stock remains?

13.

A steel frame is constructed in the welding shop
.
At one corner
,
three pieces of steel
overlap.

If their thicknesses are
3
/
8
”,
3
/
16
”,
5
/
32

what will the total thickness be?

14.

Given the following diagram
,
determine the di
s
tance
"
X
"
.

Note: You may assume that the
3
/
8
" dia. hole is centered on the width of
t
he piece

7

15.

What is the total clearance when a
5
/
16
"
bolt is inserted into a
3
/
8
"
hole?

16.

Con
v
ert each of the follo
w
ing dr
i
l
l
bit si
z
e
s
to dec
i
mal form then rearrange the
m in
order
f
rom the
s
m
a
llest
(
le
f
t
)
to the
l
argest
(
r
i
gh
t)
.

3
/
8

5
/
16

7
/
1
6

11
/
3
2

13
/
32

17.

A
¾
i
n.
w
rench is n
e
eded to loosen
a
he
x
-

What would be the decimal
si
ze
w
rench that could be u
s
ed?

18.

A speci
fi
cation calls for
t
he clearance bet
w
een piston and c
y
linder in an engine to be
3
/
64

in.

What
i
s its decimal equivalent
?
(Nearest ten

thousandth)

19.

Four sheet
s
of sheet metal have the following thicknesses:

3
/
16

in
.

11
/
16

in
.

7
/
32

in
.

1
/
8

in.

Convert these to decimal fo
r
m and then arrange them from thinnest to thickest
.

20.

You are to bore a hole which is 0
.
27 " in d
i
ameter
.

If you
have a drill bit set that is made in increments of 64ths of an inch
,
what size
dri
l
l bit will give a hole
of
at least

0
.
27
"?

21.

Two pieces o
f
metal o
v
e
r
lap as sho
w
n
.

If
th
e
s
e
a
r
e
w
elded together
,

what
is
the total length o
f
the welded piece
?

22.

Three rectangular sections of plate steel are connected by overlaps as shown below.

Using the dimensions given, f
in
d the total length of the welded section.

8

23.

A cross
-
section of steel channel as shown below has a width of 4.25 inches, with each
flange having a thickness of 0.1875 inches.

Determine the inside width of the channel
.
(
nearest thousandth)

24.

Using the diagram below
,
determine the thickness of the mai
n stem of the I
-
beam
(dimension "X")

25.

Two holes, 3.6cm and 3
.
2cm in diameter, are drilled into a 20cm long strip of steel bar as
shown below.

Using the given dimensions, find the missing dimension
,
labeled "x” that
separates the edges of the two ho
les.

26.

What is the final cost for this stock order?

Quantity

Description

Unit Price

15

¾" 8' stock

\$
3
.
49 per 8' section

10

112" 8' stock

\$
2.75 per
8'
section

25

114" 8' stock

\$
2.23 per
8'
section

9

27.

Eleven 8 inch long sections of ½” inch diameter round stock is needed.

If 0
.
125" of material is lost from each cut, what will be the total length of material
removed from a 120 inch bar? (Nearest thousandth)

28.

Thirty
-
five L
-
shaped pieces are cut from sheet metal which is 0.310" thick. The pieces
are then stacked as shown below.

Wh
at is the height of that stack of metal pieces? (Nearest thousandth)

29.

A strip of metal 20" long has four rectangular slots each 2
.
5" long stamped from it
.

If the spacing between the slots is 1
.
75", how
far

is it from the end of the metal
strip to the edge of the first slot?

30.

A 72" length of angle iron is subdivided into 7 pieces of equal length
.

If
1
/
8
" is allowed for each cut, what is the length of each piece? (Nearest
hundredth)

31.

Calculate

the weight of a product if the parts before welding have the following

weights
:

5 lengths of angle iron, each 3.6Ibs

4 lengths of bar steel, each 1
.
1lbs

2 lengths of round stock
, each 0.85 lbs.

32.

A portable welding unit was purchased at a list price of \$795

less a 10% discount plus a
5% sales ta
x
.

What is the selling price
?

20”

10

33.

A series of holes are drilled into a circular flange. The spec calls for diameters of 0.
65

in.
± 0.05"
.

Restate the
t
olerance in terms of percentage. (i
.
e
.
, 0.75 in.±
?%)

34.

The diameter
of certain round stock is 112 in
.
±0.3%.

What maximum diameter could a buyer expect from the stock?

35.

The supply of metal stock in a shop weighs about 3 tons
.

If 0
.
2 ton of this is used
,
what percentage remains? (Nearest percent)

36.

A motor is rated at 85%
efficiency
.

If it has an input power of
1
/
2
HP
,
what would be its output power? (Nearest
hundredth)

37.

A shop does \$1
3
00 worth of business one month and \$1700 worth of business the next
.

What is the rate of increase? (Nearest whole percent)

38.

A welder
.
24/hour raise.

I
f he used to get \$7.50

for
1hr
,
what is the
percent increase
in his salar
y
? (Nearest
tenth of a percent)

39.

A frame is made up of five l
-
ft sections of solid round stock steel that is 0
.
5" in diameter
each steel bar weighs 0
.
67

lbs. A solid aluminum rod with the same dimensions weighs
0
.
23 lbs.

If the aluminum rods replaced the steel bars mentioned above, what will be the
percent decrease

in weight of the frame
?

Find the measurements for the
questions 40 to 45:

40.

.

41.

11

42.

43.

44.

45.

46.

Find the weight of a 1 ft. long piece of steel round stock if the diameter is 2".

Use the formula:
lbs. per linear ft.
=
3.67
X
D2

47.

Using
t
he
i
nfo
rmation

found
in p
r
oblem #46
,
w
ha
t
'
s
th
e
w
eight o
f
a 65 ft. piece of round
stock?

48.

Find the weight of a
1
ft. piece of aluminum tubing that has dimensions W=.125"
,
and
OD=2
.
375":

U
se the formula
:
lb
s
.
p
er li
n
e
ar
ft.
=
2.69
x
(
OD
-

W
)
x
W

49.

Ho
w
much would a 23.5 ft. piec
e of the a
bove tubing weigh?

50.

A
rectangular frame measu
r
es
9
6
"

by
48"
.

F
ind the length of the diag
o
nal
,
d
i
mension C
,
using this formula:

C
=
.
J
a
2

+
b

51.

De
t
erm
i
ne the vo
l
um
e
of an o
x
ygen cylinder wi
t
h a height of 24" and a diameter of 6"
,
b
y
using this formu
l
a:

V
=
3.14
x
H
x
D
2 divided by

4

12

52.

Identify the type of angle and give its measurement.

53.

Identify the type of angle and give its measurement.

54.

Identify the type of angle and give its measurement.

55.

Find the total length of stock needed to make this table frame?

56.

Find the total area of these plates that are welded together?

13

57.

Find the area and perimeter of this flame
-
cut steel plate.

s

58.

Compare the areas of these two figures. Since the sides are the same length, are the areas
the same?

59.

Calculate the perimeter and the area of the following.

60.

Calculate the perimeter and the area of the f
ollowing.

14

61.

Calculate the perimeter and the area of the following.

62.

Calculate the perimeter
:

63.

Calculate the perimeter.

64.

Find the missing dimension. (Round to the nearest tenth.)

65.

Find the missing
dimension.

15

66.

Find the missing dimension. (Round to the nearest tenth)

67.

Find the missing dimension.

68.

Find the Area.

16

69.

Find the area. (Round to the nearest tenth)

70.

Find the area. (Round to the nearest whole number)

71.

Find the circumference. (Round to the nearest tenth)

17

72.

Find the area. (Round to the nearest tenth)

73.

Find the area. (Round to the nearest tenth)

74.

Find the area of the ring. (Round to the nearest tent
h)

75.

A welder is required to sheer
-
cut a piece of sheet steel as shown in the illustration.

After the cut piece is removed, how much sheet, in inches, remains from the original piece?

18

76.

Welded support is illustrated.

A customer
orders 34 supports
:

A.

What, in inches, is the total length of weld needed?

B.

The support plate is 13 inches long and 9 inches wide. How much 9
-
inch
-
wide bar
stock, in inches, is used for the completed order?

C.

Each support weighs 14 pounds. What is the weight
in pounds of the total order?

19

M
ake fractions out of the following information
:

(
Reduce, if possible
)

77.

An inch into 8ths

78.

Read the distances from the start of the steel tape measure to the letters. Record the

20

79.

Find

the total combined length of these 2 pieces of bar stock

80.

Find the total combined weight of these 3 pieces of steel.

21

81.

To make shims for leveling a shear, three pieces of material are welded together.

What is the total thickness of the welded
material, in inches?

82.

Determine the missing dimension on this welded bracket.

22

83.

A frame
-
cut wheel is to have the shape shown. Find the missing dimension.

84.

Three of these welded brackets are needed.

What is the total
length, in inches, of the bar stock needed for all of the brackets?

23

85.

This piece of angle is to be used for an anchor bracket.

If the holes are equally spaced, what is the measurement between hole 1 and hole
2?

86.

Nine sections of steel bar, each 12 ¼” long, are welded together. The finished piece is cut
into 4 equal parts.

What is the length of each new piece? Disregard cut waste.

87.

Round off to the nearest whole number.

a.

7.7

_________________

b.

12.1

_________________

c.

9.7

_________________

d.

17.398

_________________

88.

A welder uses 4.18 cubic feet of acetylene gas to cut one flange.

How much acetylene gas is used to cut 19 flanges?

89.

A welder shears key stock into pieces 3.75” long.

How many whole piec
es are sheared from a length of key stock 74.15” long?

24

90.

Express each decimal dimension as a fractional number.

91.

A piece of steel channel and a piece of I beam are needed. Express each dimension as a
decimal number.

25

92.

Find the length of slot 2.

93.

The fillet weld shown has 2’, plus 18” of weld on the other side of the joint.

Express the total amount of weld in feet.

94.

Six welding jobs are completed using 33 pounds, 13 pounds, 48 pounds, 14 pounds, 31
pounds, and 95 pounds of electro
des.

What is the average poundage of electrodes used for each job?

26

95.

This I Beam is 180 cm long and 14.5 cm high.
(
Round ea
places)

96.

How many square inches are in 2 square foot?

27

97.

These two triangular shapes are cut from sheet metal.

What is the area of each piece in square inches?

1.

Triangle A

________________

ii)

Triangle C ___________

98.

Two pieces of square stock are welded together.

Find, in cubic feet, the total volume of the pieces.
(
decimal places
)

28

99.

Circles A and B are cut from 3/8 steel plate.

What is the circumference of both circles in inches

and

i
n
f
eet
?

A.

__________Inches

B. _____________Inches

__________Feet

_____________Feet

100.

How many degrees are in each of these parts of a circle?

i)

1
/
3

Circle

_______________

ii)

5
/
6

Circle

_______________

101.

Find the size of ¼” plate needed to construct this semicircular
ventilation

section.

The average diameter is 19
3
/
16
.

29

102.

A weld shop supplies 104 shaft blanks, each 4” wide and 5” long.

How many can be cut from the piece of plate shown?

103.

The circular bland is used to make sprocket drives.

How many sprocket

drive blanks can be cut from a plate of steel having
the dimensions of 44” x 44”?

30

Q #

1

37 ¾

2

TO BIG

3

11
/
32,

3
/
8,

13
/
32,

7
/
12

4

BAR 1

5

27.5

6

56 STRIPS

7

24 WHOLE PIECES

8

12 ¼

9

5 ½

10

73 ½ LBS.

11

7.5 DAYS
ROUNDED

12

32
1
/
8

13

23
/
32

14

3
/
16

15

1
/
16

16

0.3125

0.34375

0.375

0.40625

0.4375

17

0.75

18

0.0469 ROUNDED

19

0.125

0.1875

0.21875

0.6875

20

18
/
64

21

13.9

22

44.5 CM.

23

3.875

24

1.5

25

5.2 CM.

26

\$135.60

27

89.375

28

10.85

29

2.375

30

10.2

31

23 LBS.

32

\$751.27

33

6.7

34

0.5025

35

96.7 ROUNDED

36

0.45 HP.

37

30.80%

38

2.90%

39

65.70%

40

2
5
/
16

41

1
7
/
16

42

4
11
/
16

43

5
3
/
16

44

9
1
/
2

45

9 ¾

46

14.68 LBS.

47

95.42 LBS.

48

1.03 LBS.

49

24.2 LBS.

50

16.73

51

678.24 CU.IN.

52

OBTUSE 112 DEG.

53

ACUTE 49 DEG.

54

RIGHT 90 DEG.

55

249.5

56

28.25 SQ. IN.

57

69 CM.

58

NOT THE SAME

59

P=36IN.

A=54SQ. IN.

60

P=91YDS.

A=390SQ. YD.

61

P=32FT.

A=45SQ. FT.

62

P=16CM.

63

P=44FT.

64

18.3IN..

65

20
IN.

66

13.7 FT.

67

86.6 MTRS.

68

4.5SQ. FT.

69

210.4SQ. FT.

70

65 SQ. FT.

71

100.5 in.

31

72

16.6 sq. mtrs

73

19.6 sq. in.

74

141.4 sq. ft.

75

17

76

272. IN

442 IN

476 LBS

77

1
/
8

IN

3
/
8

IN

½ IN

¾ IN

78

¼ in

5
/
8

IN

1 AND
1
/
8

2 AND
1
/
8

79

8 AND
5
/
8

80

29 AND
3
/
8

81

1 AND
5
/
8

82

6 AND
1
/
8

83

2 AND
9
/
16

84

53 AND
7
/
16

85

3 AND
9
/
74

86

27 AND
9
/
16

87

8

12

10

17

88

79.42CUFT

89

19 PIECES

90

9 AND ½

2 AND ¾

91

2.25 IN

0.1875 IN

6.5625 IN

92

7.0375

93

3 AND ½ FT

94

39 LBS

95

70.87 IN

5.71 IN

96

288 SQ IN

97

32 SQ IN

72 SQ IN

98

2.949 CU FT

99

A=30.35 FT

364.24 IN

B=13.345 FT

160.14 IN

100

120 DEG

300 DEG

101

¾ X

63 AND ¾ IN

102

72 PIECES

103

9 PIECES

32

Mathematical Points to Remember

and

Problem Solving Tips

Use addition in order to find the total when combining two or more
amounts.

Subtraction

Use subtraction in order to:

Determine how much remains when taking a particular amount
away from a larger amount

Determine the difference between two numbers

Multiplication

Use multiplication to find a total when there are a number of equally sized groups.

Division

Use division to:

Split a larger amount into equal parts

Share a larger amount equally amount a certain number of people or groups

Calculating Time

When solving problems that involve time, using a visual aid such as an analog

33

Time

When adding time, be careful to distinguish between A.M. and P.M
times. If you begin at a P.M. time and the elapsed time takes you past
midnight the ending time will likely be in A.M. If you start from an
A.M. time and the elapsed time takes you past noon, the ending time
will likely be in P.M. time. For instance, if you start sleeping at 10
P.M. and you sleep for 8 hours, the time you wil
l wake up is going to
be in the A.M. To calculate, add the hours, and then subtract 12 from
the total

10 + 8 = 18 hours; 18 hours

12 hours = 6 hours past midnight or 6 A.M.

Fraction/Decimal/Percent

F
raction

identifies the number of parts (top
number) divided by the
total number of pars in the whole (bottom number)

Decimal

place values to identify part of 1, written in tenths,
hundredths, thousandths, etc.

Percent

part of 100.

Remember!

A decimal number reads the same as its fractional equi
valent. For example, 0.4 = four tenths =
4
/
10
; 0.15 = fifteen hundredths =
15
/
100

When working with fraction and decimal quantities that are greater than 1,
remember that these numbers can be written as the number of wholes plus the
number of parts. For
example, 2.5 can be written as 2 + 0.5 (two wholes plus
five
-
tenths of another whole). The mixed number 2 ½ can be written as 2 + ½
(2 wholes plus half of another whole). When converting these numbers, the
whole number stays the same. Always remember to ad
d the whole number back
to the fraction or decimal after you have completed converting
.

Multiplying fractions by fractions

Decimals are named by their ending place value

tenth’s, hundredths, thousandth’s, etc. This
makes it easy to convert to fractions.

34

0.3

“3 tenths”

3
/
10

0.76

“76 hundredths”

76
/
100

0.923

“923 thousandths”

923
/
1000

1.7

“1 and 7 tenths”

1
7
/
10

When you multiply a fraction by another fraction, the result is the product of the numerators over
the product of the denominators.

4
/
5

x
2
/
3

=
8
/
15

To multiply a fraction by a decimal, convert the fraction to a decimal:

½ x .25 = .5 x .25 = .125

Basic Algebra

Basic algebra involves solving equations for which there is a missing value. This value is often
represented as a letter; such as the le
tter x or n.

Solving equations for a missing value requires you to understand opposite operations. Addition
and subtraction are opposite operations as well as multiplication and division. You use opposite
operations so that an equation can remain “balance
d” when solving the missing value.

Proportions

Multiple operations are using when solving proportions. After the proportion statement is set up,
multiply in order to find cross products. Then divide each side of the equation by the factor being
multiplied
by the unknown variable to solve for the unknown variable.

40 x
n =
16 x 8

40
n

= 128

n =

= 3

Order of Operations

When calculations require you to more than one operation, you must follow the order of
operations. Any operation containing a parenthesis must be calculated first. Exponents come next
in the order of operations, followed by multiplication and division, add
ition and subtraction
35

come last. An easy way to remember the order of operation is: PEMDAS or Please Excuse My
Dear Aunt Sally

Exponents

An exponent is an expression that shows a number i
s multiplied by itself. The base is the number
to be multiplied. The exponent tells how many times the base is multiplied by itself.

2
3

The base is 2. The exponent is 3.

2 x 2 x 2 = 8

Multiplying Negative Numbers

Multiplying negative numbers is similar to

multiplying positive numbers
except for two rules
:

When multiplying a positive number and a negative number, the

8 x (
-
6) =
-
48

When multiplying two negative numbers, the answer is always
positive.

-
2 x (
-
7) = 14

By knowing the rules of multiplying positive and negative numbers, you can rule out
incorrect answers before performing any calculations.

Perimeter Measures

Perimeter measures the length of the outer edge of a shape. The space enclosed within this edge
is

measured by area. Area is a two
-
dimensional measurement that measures the number of square
units of a surface.

36

Formulas for Perimeter and Area of Rectangles

To understand the formulas for finding perimeters and area, consider the figure on the next
page
, which is 3 units wide by 5 units long.

Perimeter: by counting the number of units on each side of the rectangle, you find that
the perimeter is 16 units.

Area
: Area is a 2 dimensional (2D) measurement that measures a surface. By counting
the total number

of squares that make up the rectangle, you find that its area is 15 square
units. So the formula is:

area = length x width

Volume is a 3 dimensional (3D) measurement that measures the amount of space taken up by an
object. Like area,
you need to know the length and width of an object in order to calculate
volume. In addition to this, you need to know the object’s height. Volume is measured in cubic
units.

Use the formula V = 1 x W x h

Convert Measurements

In the United States, there
are two systems of measurements; the
traditional (standard) system and the metric system. Gasoline is usually
sold by the gallon (standard), and large bottles of soda are sold by the
liter (metric).

The Metric System

The metric system of measurement is use
d by most of the world. Units
of length are measured in centimeters, meters, and kilometers. Units of
volume (capacity) include liters and milliliters. Units of weight include
milligrams, grams, and kilograms. The metric system follows the base
-
10 system
of numeration.
This system is commonly used in sciences and medicine.

37

The Customary/Standard System

The customary or standard system of measurement is the system most commonly used in
everyday life in the United States. Units of length include inches, fee
t, and miles. Units of
volume include cups, quarts, and gallons. Units of weight include ounces, pounds and tons.
Unlike the metric system, the standard system of measurement does not follow the base
-
10
system.

If you are unsure of whether to multiply or
divide to convert from one unit of measurement to
another, you can set up the problem as a proportion. Here is an example:

=

By finding the cross products, you see that:

0.264x = 21

The final step needed to solve is to divide both sides of the equation by 0.264, which gives you
x = 79.5 liters
.

What’s the best deal? Use Ratios and Proportions to find the outcome

A rate is a kind of ratio. Rates compare two quantities
that have different units of
measure, such as miles and hours
.

Unit Rates

Unit rates have 1 as their second term. An example of unit rate is \$32 per
hour.

Another example of a unit rate is \$6 per page

Proportions

Proportions show equivalent ratios. You may find it helpful to use proportions to solve problems
involving rates. Calculate the total cost based on the hourly rate.

To find the total cost based on an hourly rate, multiply the number of hours worked by the

hourly
rate.

=

Convert Between Systems of Measurement

When solving problems that involve converting from one unit of
measurement to another, you typically should first determine to which unit of
measurement you should be converting.

For example:

You are the service manager for a corporation and are responsib
le for a fleet
of vehicles. You need to determine which brand of engine oil to use with
your fleet. There are two brands that you are deciding between. So, you decided to run a test
between the two brands. On average, a vehicle burned 5 milliliters of the
more expensive
38

synthetic blend. The average consumption of regular engine oil was 64 milliliters. Each vehicle
holds 5.8 quarts of engine oil. What percentage of the regular oil was lost during the test?

A. 0.5%

B. 1.2%

C. 3.2%

D. 5.6%

E. 9.1%

Plan for Suc
cessful Solving

to do?

What are the
facts?

How do I find

Is there any
unnecessary
information?

What prior
knowledge will
help me?

Find the percent
of regular engine
oil that was used

The engine holds
5.8 quarts, 64 ml
of oil
was lost

Convert one
measurement to
the same system
as the other.

Calculate the
percentage that
was lost.

5 milliliters of
the synthetic oil
was consumed

1 gallon = 4 qts.

4 quarts = 1 liter

1 liter = 0.264
gal.

1 liter = 1,000
milliliters

Confirm your

understanding of the problem and revise your plan as needed.

I am going to convert the quarts
to milliliters and then find the percent of the total that was lost.

5.8 quarts ÷ 4 = 1.45 gallons

Divide to convert

quarts to gallons

1.45 gallons ÷ 0.264 ≈ 5.492 liters

Divide to convert gallons to liters

5.492 liters x 1,000 = 5,492 milliliters

Multiply to convert liters to milliliters

= 0.012 x 100% = 1.2%

Divide the amount of oil that was lost by the initial
total to calculate the percent of lubricant that was
consumed.

Check your answer. You can solve the problem another way by converting the milliliters
to quarts and finding the per
cent.

B. 1.2%

By converting the units of measure to the same system, you can calculate the percent of
oil lost in the test by dividing the amount consumed by the total capacity and multiplying
by 100%

The symbol ≈ mean
s “approximately equal to” and is used because the
conversion formula between gallons and liters is not exact. When
calculating conversions between measurements for which the
conversions are not exact, you must take into account the fact that the
numbers a
re often rounded at some point during the calculation
39

BASIC ALGEBRA RULES

1.

DO BRACKETS FIRST

Example: ( ) [ ]

2.

WHEN YOU ARE ADDING OR SUBTRACTING NUMBERS:

IF YOU HAVE MORE POSITIVES THAN NEGATIVES NUMBERS YOUR

Example:
-
4 + 7 equals +3

3.

WHEN YOU ARE ADDING OR SUBTRACTING NUMBERS:

IF YOU HAVE MORE NEGATIVES THAN POSITIVES NUMBERS YOUR

Example:
-
7 + 4 equals
-
3

4.

WHEN YOU ARE MULTIPLYING OR DIVIDING NUMBERS

LIKE SIGNS ARE POSITIVE AND UNLIKE SIGNS ARE MINUS

Example: (+ and + or
-
+
-

+) equal a plus sign

(
-

and +) equals minus

5.

LIKE EXPONENTS CAN ONLY BE ADDED TOGETHER

Example: x to the second power can be combin
ed

With another x to the second power only

6.

WHEN YOU ARE MULTIPLYING WHOLE NUMBERS

7.

THEY ARE MULTIPLIED, AND EXPONENTS ARE ADDED TOGETHER

Example: 3x to the third power times 2x to the second power

equals 6x to t
he fifth power

8.

WHEN YOU DIVIDE NUMBERS THEY ARE DIVIDED AS USUAL AND
EXPONENTS ARE SUBTRACTED FROM EACH OTHER

Example: 16m to the third power divided by 4m

equals 4m to the second power

40

41

Formulas 1

Gear Ratio

=

Number of Teeth on the Driving

Gear

Number of Teeth on the Driven

Gear

Reduce to Lowest Terms

Pulley Ratio =
Diameter of Pulley A

Diameter of Pulley B

Reduce to Lowest Terms

Compression Ratio =
Expanded Volume

Compressed Volume

Reduce to Lowest Terms

A Proportion is 2 Ratios that are =

Example
1
/
3

=
4
/
12

Cross Product Rule

A
/
B

=
C
/
D

or A x D = B x C

Pitch =

Rise

Run

Changing a Decimal to a %

Multiply by 100

Changing a Fraction to a %

Divide the Numerator by the
Denominator and Multiply by 100

Changing a % to a Decimal

Divide by 100

P
/
B

=
R
/
100

When P is unknown

When R is unknown

When B is unknown

Changing a decimal to a fraction

.375 hit 2
nd

hit prb hit enter

Sales Tax

Sales Tax

=
Tax Rate

Cost 100

Interest

Annual Interest

=
Annual Interest
Rate

42

Principal 100

Commission

Commission Sales

=
Rate

Sales 100

Efficiency

Output

=
Efficiency

Input 100

Tolerance

Tolerance

=
% of Tolerance

Measurement 100

% of Change

Amount of Increase
=

% of
Increase

Original Amount 100

Discounts

Sales Price = List Price

Discount

43

44

45

46

PERCENT
PROBLEMS

The Percent (%)

The Whole (OF)

The Part (IS)

47

Trig Formulas

1.

Change an angle to radians = angle times pie divided by 180

2.

Change an angle to degrees = radians times 180 divided by pie

3.

30 deg., 60 deg., 90 deg., triangle; the short end is
equal to ½ the hypotenuse or the
hypotenuse = 2 times the short end

4.

45 deg., 45 deg., 90 deg., triangle

the 2 shorter sides are the same length and the
hypotenuse is 1.4114 times the leg

5.

Find trig value

put in SIN, COS, or TAN followed by degrees and
hit enter

6.

Find acute angle X

hit 2
nd

button, then SIN, COS, or TAN; enter number and hit equals. Hit
RP move arrow to DMS hit enter twice

You would use this when you need an answer in degrees, minutes, and or seconds

7.

Find acute angle X

hit 2
nd

button,
then SIN, COS, or TAN; enter number and hit equals.
You would use this when you need an answer in degrees.

48

Applied Mathematics Formula Sheet

Distance

1 foot = 12 inches

1 yard = 3 feet

1 mile = 5,280 feet

1 mile ≈ 1.61 kilometers

1 inch = 2.54
centimeters

1 foot = 0.3048 meters

1 meter = 1,000 millimeters

1 meter = 100 centimeters

1 kilometer = 1,000 meters

1 kilometer ≈ 0.62 miles

Area

1 square foot = 144 inches

1 square yard = 9 square feet

1 acre = 43,560

Volume

1 cup = 8 fluid ounces

1 quart

= 4 cups

1 gallon = 4 quarts

1 gallon = 231 cubic inches

1 liter ≈ 0.264 gallons

1 cubic foot = 1,728 cubic inches

1 cubic yard = 27 cubic feet

1 board = 1 inch by 12 inches by 12 inch

Weight

1 ounce ≈ 28.350

1 pound = 16 ounces

1 pound ≈ 453.592 grams

1
milligram = 0.0001 grams

1 kilogram = 1,000 grams

1 kilogram ≈ 2.2 pounds

1 ton = 2,000 pounds

Rectangle

perimeter = 2(length + width)

area = length x width

Rectangle Solid (Box)

volume = length x width x height

Cube

volume = (length of side)
3

Triangle

sum of angles = 180
o

area = ½(base x height)

Circle

number of degrees in a circle = 360
o

circumference ≈ 3.14 x diameter

2

Cylinder

2

x height

Cone

volume

2

× height

3

Sphere (Ball)

volume ≈
4
/
3

3

Electricity

1 kilowatt
-
hour = 1,000 watt
-
hours

Amps = watts ÷ volts

Temperature

o
C = 0.56(
o
F
-
32)
or

5
/
9
(
o
F
-
32)

o
F = 1.8(
o
C) + 32
or

(
9
/
5

x
o
C) + 32
49