# of the resultant of the concurrent force system below

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25 Νοε 2013 (πριν από 5 χρόνια και 1 μήνα)

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60 kN

100 kN

130 kN

Q.1 Determine the magnitude, sense, and direction

of the resultant of the concurrent force system below

5

12

3

4

60
0

A

25 kN

25 kN

19 kN

10 kN

2 m

2 m

2 m

3 m

Q2. Calculate the net moment about point A due to the

forces shown below

1.
Types of Supports

2.
Types of Beams

3.
Calculate Reactions

4.
Draw/sketch Shear Force
Diagram(SFD)

5.
Draw/sketch Bending Moment
Diagram(BMD)

Beam is the most common structural member

They are sometimes referred by other names,
indicative of some specialized function such
as girder (penopang),stringer, purlins or
joists.

The concepts of shear and bending in
statically determinate beam only.

Deflection is directly proportional to the load

2) Span

Deflection is proportional to the cube of the
span

3) Size and shape of beam

The greater the size of beam, the less the
deflection.

Deflection is inversely proportional to the
moment of inertia

4) Stiffness of material

The stiffer the material, the greater its
resistance to bending, the less will be the
deflection.

Table 11.1 Values of coefficient c for
deflection formula δ=cWl
3
/EI

A 406 x 178 UB 54 is simply supported at the
ends of a span of 5 m carries a uniformly
distributed load of 60 kN/m. Calculate the
maximum deflection given E = 205 000
N/mm
2

From Table 11.1

δ = 5Wl
3
/384 EI

where W = 60 x 5 = 300
kN

= 3 x 10
5

N

l = 5000 mm

E = 205 000 N/mm
2

I = 164.6 x 10
6

mm
4

δ = (5/384) x {(300 000 x 125 x 10
9
)/ (205
000 x 164.6 x 10
6
)}

= 14 mm