# Chapter -05

Δίκτυα και Επικοινωνίες

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Chapter
-
05

October 2, 2008

1

CSCI 5132

Internet Protocols

Solution Set

1. A router with IP address 125.45.23.12 and Ethernet physical address 23:45:AB:4F:67:CD has
received a packet for the host destination with IP address 125.11.78.10 and Ethernet physical
address AA:BB:A2:4F:67:CD. Show the entries in the ARP

request packet sent by the router.
Assume no subnetting.

OX 0001

OX 0800

OX 06 OX 04

OX 0001

OX 23:45:AB:4F:67:CD

Ox 7D:2D:17:0C

Ox 00:00:00:00:00:00

Ox 7D:0B:4E:0A

2. Show

the entries in the ARP packet sent in response to above example.

OX 0001

OX 0800

OX 06 OX 04

OX 0002

AA:BB:A2:4F:67:CD

Ox 7D:0B:4E:0A

OX 23:45:AB:4F:67:CD

Ox 7D:2D:17:0C

3. Encapsulate the result
of ex. 1 in data link frame.

Chapter
-
05

October 2, 2008

2

CSCI 5132

Internet Protocols

4. Encapsulate the result of ex. 2 in data link frame.

Same as above fig. the data part will be raplaced by the ans of q.2 and the destination address
will be: AA:BB:A2:4F:67:CD. And the source address field will be OX 23
:45:AB:4F:67:CD.

5. Is the size of ARP packet fixed? Explain?

No, it can have different lengths (bytes)